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The 350 is a 180 degree engine....(Crank throws and piston positions are 180* off each other)....Because the camshaft rotates at half speed (compared to the crank),and each "stroke" is a half rotation of the crankshaft, here are the relative positions/(strokes) of the two sides (piston and crank):

Starting at LTDC; (we'll call this crank position A, cam A)
(L.exhaust closes, L. intake valve opens)---.[Left piston going down from TDC on intake stroke ---R. ex valve opens) Right coming up from BDC on exhaust stroke (Crank turns 180*, camshaft turns 90*)

RTDC; (Crank position B, cam B)
L.intake closes) Left going up on compression stroke---R.exhaust closes, R. intake opens) right down on intake (crank turns 180* and cam 90*)

At this point, the crank has rotated 360*, and the cam 180*

LTDC; (crank position C, cam C)
(left ignition), Left down on power stroke(Both L. valves remain closed)---R. intake closes)Right up on compression (crank 180*, cam 90*)(ALL valves closed)

RTDC; Crank position D, cam D)
(L. exhaust opens )Left up on exhaust--- (right ignition), Right down on power stroke (both R.valves closed)(crank 180*, cam 90*)

You will note that the points fire at 90*apart and "rest" for 270* when viewed at the camshaft end , and that this complete 4-stroke cycle has required 720*of crank rotation and 360* at the cam....

Now, let's see what happens if we advance(or retard) the camshaft by 180*.....
Since the sequence now starts Crank position A, cam C (cam C is plus or minus 180* from the original cam A position)
and continues to Crank B, cam D... then crank C, cam A ...then Crank D, cam B, you would think the engine wouldn't run, BUT, Crank A and Crank C are actually the same,( both LTDC) so if the points are timed to fire at the end of the appropriate compression strokes, it runs.....

EDIT: ...Sure, figure it out while I'm composing this long reply.......LMAO!...... :lol:
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